Find the remainder when x^3--ax^2+6x-a is divided by x-a . [ncert]

                           

Let p(x)=x^3-ax^2+6x-a.  - - - - - - (1)

Now put x-a=0 => x=a

Put x=a in (1), we get,

p(a)=a^3-a.a^2+6a-a

p(a)=a^3-a^3+5a

p(a)= 5a

So remainder = 5a Ans.