Saturday, 28 June 2025

Thursday, 26 June 2025

Rationalise the denominator 1÷(7+5√2).

 Given that 1÷7+5√2

= 1/(7+5√2)

Multiplying numerator and denominator by

7-5√2 , we get,

{1×(7-5√2)}/{(7+5√2)(7-5√2)}

=(7-5√2)/{7²-(5√2)²}.  

[By using (a+b)(a-b)=a²-b²]

=(7-5√2)/(49-50)

=(7-5√2)/(-1) = -(7-5√2) =-7+5√2.  Ans.

Check whether 7+3x is a factor of 3x^3+7x ? [ncert]

                               Now take 7+3x=0 =>3x= -7 => x= -7/3 => If p(x)=3x^3+7x , then, => p(-7/3) = 3(-7/3)^3+7(-7/3) =...