(i) (x + 2y + 4z) * iii * (- 2x + 3y + 2z) ^ 2
We know that (a + b + c)² = a²+ b²+ c²+ 2ab + 2bc + 2ca
(i) (x + 2y + 4z)² = (x)² + (2y)²+ (4z)²+ 2(x)(2y)+2(2y)(4z) + 2(4z)(x)
= x² + 4y²+ 16z² + 4xy + 16yz + 8zx Ans.
(ⅱ) (- 2x + 3y + 2z)²=(-2x)²+(3y)²+(2z)² +2(-2x)
(3y)+2(3y)(2z) + 2(2z)(- 2x)
= 4x²+9y²+4z²-12xy+12yz-8zx Ans.
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