Given that 4√3x² +10x+√3=0
Comparing the given quadratic equation with standard quadratic equation ax²+bx+c=0
So a=4√3, b=10 and c=√3
The discriminant D=b²-4ac
=> D=(10)²-4(4√3)(√3). [Here √3×√3 = 3]
=> D=100-4(12)
=> D=100-48
=> D=52 Ans.
If find x. 1/(9!) + 1/(10!) = x/(11!).
Here n! is read as n factorial. It can be written as n(n-1)! or n(n-1)(n-1)!
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