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What is the gradient of a line whose angle of inclination is 150° ?
We know that gradient of a line is The
slope of this very line.
Let m be the slope of the given line, then,
Gradient =m= tan150°
=tan(180°-30°) = - tan 30° = -1/√3 Ans.
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If find x. 1/(9!) + 1/(10!) = x/(11!).
Here n! is read as n factorial. It can be written as n(n-1)! or n(n-1)(n-1)!
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